VMware Certified Professional - Data Center Virtualization (VCP-DCV) Practice Exam

Which change in Storage Policy would reduce storage consumption by one third?

1. Number of failures to tolerate = 1

2. Number of disk stripes per object = 2

3. Number of failures to tolerate = 3

4. Number of disk stripes per object = 1

The correct answer is: Number of failures to tolerate = 1

Choosing to set the number of failures to tolerate at one is the correct answer for reducing storage consumption by one third. This setting determines how many simultaneous failures can be tolerated for the stored data. When this value is set to one, the system can continue to operate even if one disk fails, which allows for a more efficient use of disk resources compared to higher tolerances. In scenarios with a failure tolerance of one, the data is replicated across the disks in such a way that only a minimal amount of additional disk space is used for redundancy. By contrast, higher tolerances, such as three, would require significantly more storage capacity for maintaining additional copies of the data to cover those failures. The number of disk stripes per object setting affects performance and data distribution but does not directly correlate with a fixed percentage reduction in storage consumption. When set to two, it increases the storage overhead because more stripes mean that more space is effectively being reserved for redundancy. Lowering the stripes to one might help with efficiency but would not necessarily lead to the one-third reduction in consumption since it primarily influences how data is segmented rather than overall redundancy. In summary, setting the number of failures to tolerate at one effectively reduces the redundancy required in the storage setup, which leads to